Butane, C4H10C4H10, reacts with oxygen, O2O2, to form water, H2OH2O, and carbon dioxide, CO2CO2, as shown in the following chemical equation: 2C4H10(g)+13O2(g)→10H2O(g)+8CO2(g)2C4H10(g)+13O2(g)→10H2O(g)+8CO2(g) The coefficients in this equation represent mole ratios. Notice that the coefficient for water (10) is five times that of butane (2). Thus, the number of moles of water produced is five times the number of moles of butane that react. Also, notice that the coefficient for butane (2) is one-fourth the coefficient of carbon dioxide (8). Thus, the number of moles of butane that react is one-fourth the number of moles of carbon dioxide that you produce. But be careful! If you are given the mass of a compound, you must first convert to moles before applying these ratios. Calculate the mass of water produced when 9.81 gg of butane reacts with excess oxygen. Express your answer to three significant figures and include the appropriate units.
Butane, C4H10C4H10, reacts with oxygen, O2O2, to form water, H2OH2O, and carbon dioxide, CO2CO2, as shown in the following chemical equation: 2C4H10(g)+13O2(g)→10H2O(g)+8CO2(g)2C4H10(g)+13O2(g)→10H2O(g)+8CO2(g) The coefficients in this equation represent mole ratios. Notice that the coefficient for water (10) is five times that of butane (2). Thus, the number of moles of water produced is five times the number of moles of butane that react. Also, notice that the coefficient for butane (2) is one-fourth the coefficient of carbon dioxide (8). Thus, the number of moles of butane that react is one-fourth the number of moles of carbon dioxide that you produce. But be careful! If you are given the mass of a compound, you must first convert to moles before applying these ratios. Calculate the mass of water produced when 9.81 gg of butane reacts with excess oxygen. Express your answer to three significant figures and include the appropriate units.
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Chapter3: Calculations With Chemical Formulas And Equaitons
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Butane, C4H10C4H10, reacts with oxygen, O2O2, to form water, H2OH2O, and carbon dioxide, CO2CO2, as shown in the following chemical equation:
2C4H10(g)+13O2(g)→10H2O(g)+8CO2(g)2C4H10(g)+13O2(g)→10H2O(g)+8CO2(g)
The coefficients in this equation represent mole ratios. Notice that the coefficient for water (10) is five times that of butane (2). Thus, the number of moles of water produced is five times the number of moles of butane that react.
Also, notice that the coefficient for butane (2) is one-fourth the coefficient of carbon dioxide (8). Thus, the number of moles of butane that react is one-fourth the number of moles of carbon dioxide that you produce.
But be careful! If you are given the mass of a compound, you must first convert to moles before applying these ratios.
Calculate the mass of water produced when 9.81 gg of butane reacts with excess oxygen.
Express your answer to three significant figures and include the appropriate units.
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