Give a clear handwritten with explanation..and choose correct answer and explain each point..? लकाकै्याककालैण केर कीन्जाकद तेवंची गण्डकेलाड ,:-the28) +2e-- 2 F c१9,)६० - +..87vC५°- c५१)+ 2e-> ५(१)१৭) + 2e- -C५८१)हु० - + o.34vSm+ (৭৭)+,e- Scs) ४ -- ०.1५0Smzt(१৭)+2e~ Sn(s) ध°: - ०.1५)A15F( q%)+ 3e* > त\(५)६० - - \ 66 vNqf cq৭) + e- Nq cs) ह° 2 - 2+ 10फ्राटटी नी म बळनणe थेटनकाड o7 JD wজহवपCए Sकम (वक्ातक त्पड वकव Bा33 (वक्)विक)৫) A131 ११] and Nq q৭)*(११)c५ ८S) व) मा ए)वम N१ (s)(৮) e-(qq) १7 क

The Substance having lower Reduction potential will behave As reducing Agent . They Will reduce…

Cकलकालैय Aकर कोन्जाकद्र नवाने गण्डतक:- toltawing hatf reartions- gitze-- 2F Caq) ヘt8.1t3 C42t caq)t 2e-→ c4cs) co ato.34U Smzt Ca9)+ze-→ sncs) E° = -o14 A13F C aa 1+ 3e- → AICS) Nat ca9) e-→ NacCS). g° = - 271V फ्रोटटी नी बळनणह एतमकाड o7 JDN ा जटवंप Sकम (वकात a) cu(s) and A134 c4e) 1A134 (a9| and Ng°caa) (b) F-(94) and c4 (S)

Cकलकालैय Aकर कोन्जाकद्र नवाने गण्डतक:- toltawing hatf reartions- gitze-- 2F Caq) ヘt8.1t3 C42t caq)t 2e-→ c4cs) co ato.34U Smzt Ca9)+ze-→ sncs) E° = -o14 A13F C aa 1+ 3e- → AICS) Nat ca9) e-→ NacCS). g° = - 271V फ्रोटटी नी बळनणह एतमकाड o7 JDN ा जटवंप Sकम (वकात a) cu(s) and A134 c4e) 1A134 (a9| and Ng°caa) (b) F-(94) and c4 (S)

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter7: Statistical Data Treatment And Evaluation

Section: Chapter Questions

Problem 7.10QAP

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