(c) The elevator decelerates at a rate of 0.35 8² (i) Newton's Law in the y-direction can be written as: Instruction: If a is the magnitude of the acceleration, pick "1" if the acceleration is upwards, pick "-1" if the acceleration is downwards, and pick "0" if there is no acceleration. for 2.75 s. ΣF₁=T-m₂g= x mea (ii) Calculate the tension in the cable supporting the elevator. T= N (iii) How high has the elevator moved during this time? Ay= (d) What is the total distance the elevator has moved up? Ay net m m

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Chapter2: Newton's Laws
Section: Chapter Questions
Problem 19P: . Under certain conditions, the human body can safely withstand an acceleration of 10 g. (a) What...
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can someone help me answer all of part C please? Thank you

1. An elevator shown below filled with passengers has a mass of 1700 kg. The elevator does motions (a)
through (c) in succession.
T
y
L.
X
I
meg
For each of the parts below draw a free body diagram of the elevator in your notebook for each of the
parts (a) to (c). Draw the acceleration and velocity vectors in the boxes.
m
E
(a) The elevator accelerates upward from rest at a rate of 0.75
2
S
a
V
for 1.5 s.
Transcribed Image Text:1. An elevator shown below filled with passengers has a mass of 1700 kg. The elevator does motions (a) through (c) in succession. T y L. X I meg For each of the parts below draw a free body diagram of the elevator in your notebook for each of the parts (a) to (c). Draw the acceleration and velocity vectors in the boxes. m E (a) The elevator accelerates upward from rest at a rate of 0.75 2 S a V for 1.5 s.
(c) The elevator decelerates at a rate of 0.35 for 2.75 s.
2
s²
S
(i) Newton's Law in the y-direction can be written as:
Instruction: If a is the magnitude of the acceleration, pick "1" if the acceleration is upwards, pick
"-1" if the acceleration is downwards, and pick "0" if there is no acceleration.
ΣF₁=T-m₂g=
xm a
(ii) Calculate the tension in the cable supporting the elevator.
T=
✓N
(iii) How high has the elevator moved during this time?
Ay=
✔m
(d) What is the total distance the elevator has moved up?
Ay net =
Reflect: In which case, is the tension in the chord pulling the elevator the greatest? Why? Does the
tension always equal the weight of the elevator?
✓
m
Transcribed Image Text:(c) The elevator decelerates at a rate of 0.35 for 2.75 s. 2 s² S (i) Newton's Law in the y-direction can be written as: Instruction: If a is the magnitude of the acceleration, pick "1" if the acceleration is upwards, pick "-1" if the acceleration is downwards, and pick "0" if there is no acceleration. ΣF₁=T-m₂g= xm a (ii) Calculate the tension in the cable supporting the elevator. T= ✓N (iii) How high has the elevator moved during this time? Ay= ✔m (d) What is the total distance the elevator has moved up? Ay net = Reflect: In which case, is the tension in the chord pulling the elevator the greatest? Why? Does the tension always equal the weight of the elevator? ✓ m
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