I need help with this homework question. Including all steps of mass mass stoichiometry. I have no idea how to do this C. If 1.87 grams of NaHCO3 is decomposed,how many grams of NazCO3 will be produced?NaHCO3 → NazCO3 + CO2+H2O198.1983g2 NaHCO3(s) –N22CO3(s) + C02(g) + H2O(g)Page

From the balanced chemical equation the following calculation is Given for the grams of Na2CO3

Answered: C. If 1.87 grams of NaHCO3 is…

C. If 1.87 grams of NaHCO3 is decomposed, how many grams of Na2CO3 will be produced? NaHCO3 > NazCO3 + CO2 + H20 198.1983g 2 NaHCO3(s) - Na2CO3(s) + C02(g) +H2O(g)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter12: Chemical Kinetics

Section: Chapter Questions

Problem 54E: DDT (molar mass = 354.49 g/mol) was a widely used insecticide that was banned from use in the United...

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Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.

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I need help with this homework question. Including all steps of mass mass stoichiometry. I have no idea how to do this

C. If 1.87 grams of NaHCO3 is decomposed,
how many grams of NazCO3 will be produced?
NaHCO3 → NazCO3 + CO2+
H2O
198.1983g
2 NaHCO3(s) –N22CO3(s) + C02(g) + H2O(g)
Page

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