Answered: Caculate the consentration of H3O+ in a…

Chemistry by OpenStax (2015-05-04)

1st Edition

ISBN:9781938168390

Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser

Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser

Chapter15: Equilibria Of Other Reaction Classes

Section: Chapter Questions

Problem 39E: What [F-] is required to reduce [Ca2+] to 1.0104M by precipitation of CaF2?

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Question

Caculate the consentration of H3O+ in a solution that contains 5.5 * 10-5 M HO- at 25 degreese C.

Expert Solution

Step 1 To Calculate

$G i v e n, [O H^{-}] = 5.5 \times 10^{- 5} M a t 25 ° C w e a r e a s k e d t o c a l c u l a t e t h e c o n c e n t r a t i o n o f [H_{3} O^{+}] .$

Step 2 Formula used and calculation

$T h e c o n c e n t r a t i o n o f H_{3} O^{+} i s a s f o l l o w s, t h e K_{w} o f w a t e r a t 25 ° C i s g i v e n b y, K_{w} = [H_{3} O^{+}] . [O H^{-}] [H_{3} O^{+}] = \frac{K_{w}}{[O H^{-}]} [H_{3} O^{+}] = \frac{1.0 \times 10^{- 14}}{5.5 \times 10^{- 5}} (K_{w} = 1.0 \times 10^{- 14} a t 25 ° C) [H_{3} O^{+}] = 0.18 \times 10^{- 14 + 5} M [H_{3} O^{+}] = 0.18 \times 10^{- 9} M [H_{3} O^{+}] = 1.8 \times 10^{- 10} M$

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