Determine the moles of Acetic Acid (CH3COOH) required to neutralize 12.3 ml of 0.130 molar Sodium Hydroxide (NaOH) solution. NaOH(aq) + CH3COOH(aq)→ CH3COONA(aq) + H20(1) O A 0.00130 moles OR 0.00160 moles 0.00190 moles C. 0.00220 moles O D 0.00250 moles O E. >A Moving to another question will save this response. a

Introductory Chemistry: A Foundation
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Problem 87QAP: 87. What volume of 0.151 N NaOH is required to neutralize 24.2 mL of 0.125 N H2SO4? What volume of...
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uestion 1
Determine the moles of Acetic Acid (CH3COOH) required to neutralize 12.3 ml of 0.130 molar Sodium Hydroxide (NaOH) solution.
NaOH(aq)+ CH3COOH(aq)→CH3COONA(aq) + H2O(1)
0.00130 moles
A.
O
0.00160 moles
B.
OC 0.00190 moles
0.00220 moles
OD.
0.00250 moles
OE.
A Moving to another question will save this response.
a
acer
A S
P
Transcribed Image Text:uestion 1 Determine the moles of Acetic Acid (CH3COOH) required to neutralize 12.3 ml of 0.130 molar Sodium Hydroxide (NaOH) solution. NaOH(aq)+ CH3COOH(aq)→CH3COONA(aq) + H2O(1) 0.00130 moles A. O 0.00160 moles B. OC 0.00190 moles 0.00220 moles OD. 0.00250 moles OE. A Moving to another question will save this response. a acer A S P
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