Mm.44.Subject:- Chemistry says -319 is wrongan sourcesmy sourcesSCalculate AGO at 595 K forusing the following data:H₂O(g) + 1/2O2(g) H₂O2(g)AGO=-319ccleats Monthly IncomesH2(g) +O2(g) H₂O2(g)K = 3.7 x 10³7Submit Answer2H2(g) + O2(g) 2H₂O(g)K = 2.6 x 106 at 595 Kat 595 Kkj/molAn error has been detected in your answer. Check for typos,miscalculations etc. before submitting your answer.Try Another Version1 item

We have the reactions H2+O2↔H2O2 K1=3.7×10372H2+O2 ↔2H2O K2=2.6×106 Final reaction :…

Answered: Calculate AGO at 595 K for H₂O(g) + 1/2…

Calculate AGO at 595 K for H₂O(g) + 1/2 O2(g) H₂O2(g) using the following data: H2(g) +O2(g) H₂O2(g) K= 3.7 x 10³7 at 595 K 2H2(g) + O2(g) 2H₂O(g) K= 2.6 x 106 at 595 K AGO = -319 kj/mol

Chemistry: An Atoms First Approach

2nd Edition

ISBN:9781305079243

Author:Steven S. Zumdahl, Susan A. Zumdahl

Publisher:Steven S. Zumdahl, Susan A. Zumdahl

Chapter7: Chemical Energy

Section: Chapter Questions

Problem 137MP: A gaseous hydrocarbon reacts completely with oxygen gas to form carbon dioxide and water vapour....

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Question

Mm.44.

Subject:- Chemistry

says -319 is wrong
an sources
my sources
S
Calculate AGO at 595 K for
using the following data:
H₂O(g) + 1/2O2(g) H₂O2(g)
AGO=-319
c
cleats Monthly Incomes
H2(g) +O2(g) H₂O2(g)
K = 3.7 x 10³7
Submit Answer
2H2(g) + O2(g) 2H₂O(g)
K = 2.6 x 106 at 595 K
at 595 K
kj/mol
An error has been detected in your answer. Check for typos,
miscalculations etc. before submitting your answer.
Try Another Version
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