   Chapter 5, Problem 31PS

Chapter
Section
Textbook Problem

A volume of 1.50 L of argon gas is confined in a cylinder with a movable piston under a constant pressure of 1.22 × 105 Pa. When 1.25 kJ of energy in the form of heat is transferred from the surroundings to the gas, the internal energy of the gas increases by 1.11 kJ. What is the final volume of argon gas in the cylinder?

Interpretation Introduction

Interpretation:

The final volume of argon gas under a constant pressure has to be determined.

Concept Introduction:

The internal energy, U is the sum of kinetic energy and the potential energy inside the system.

Change in internal energy,ΔU, is the measures of energy that is transferred as heat and work from the system or to the system.

ΔU=qp+Wp

Where q = heat energy absorbed or released, W =work done to the system or from the system.

W=-P(ΔV) , ΔV is the change in volume, and P is the pressure.

Explanation

Given,

Initial volume =1.50L

qp=1.25kJ

Pressure=1.22×105P

ΔU=1.11kJ

Substitute in ΔU=qp+-P(ΔV) as,

1

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