Calculate ∆H°25° for the reaction: Fe3O4(s) + 2 C(s, graphite) → 3 Fe(s) + 2 CO2(g) from the following data:  2 Fe(s) + 32 O2(g) → Fe2O3(s) ∆H°25°C = –826 kJ Fe(s) + ½ O2(g) → FeO(s) ∆H°25°C = –272 kJ FeO(s) + Fe2O3(s) → Fe3O4(s) ∆H°25°C = –1121 kJ C(s, graphite) + O2(g) → CO2(g) ∆H°25°C = –394 kJ

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