Calculate E, and AG for the following cell reactions at 25 °C. [Mg 2+]= 0.032 M, [Sn 2+]=0.018 M E°sn2+/Sn = -0.14 V 2+ 2+ Mg (s) + Sn (aq)→ Mg (aq) + Sn (s) kj E = 2.22 V, AG = -429 mol kj O E = 2.22 V, AG = 429 mol kj O E = -2.22 V, AG = -429 mol kj E = -2.22 V, AG = 429 mol
Calculate E, and AG for the following cell reactions at 25 °C. [Mg 2+]= 0.032 M, [Sn 2+]=0.018 M E°sn2+/Sn = -0.14 V 2+ 2+ Mg (s) + Sn (aq)→ Mg (aq) + Sn (s) kj E = 2.22 V, AG = -429 mol kj O E = 2.22 V, AG = 429 mol kj O E = -2.22 V, AG = -429 mol kj E = -2.22 V, AG = 429 mol
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter19: Electrochemistry
Section: Chapter Questions
Problem 19.127QP
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![Calculate E, and AG for the following cell reactions at 25 °C. [Mg 2+]= 0.032 M, [Sn 2+]=0.018 M
E°sn2+/Sn = -0.14 V
Mg (s) +
Sn 2+ (aq)→ Mg 2+ (aq) + Sn (s)
kj
O E = 2.22 V, AG = -429
mol
kj
E = 2.22 V, AG = 429
mol
kj
O E = -2.22 V, AG = –429
mol
kj
E = -2.22 V, AG = 429
%3D
mol](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F50e616f2-8135-4b47-ade8-a09021bde1af%2F0f32eef5-f02f-4313-b8c0-b0320beed643%2Fehrg3zg_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Calculate E, and AG for the following cell reactions at 25 °C. [Mg 2+]= 0.032 M, [Sn 2+]=0.018 M
E°sn2+/Sn = -0.14 V
Mg (s) +
Sn 2+ (aq)→ Mg 2+ (aq) + Sn (s)
kj
O E = 2.22 V, AG = -429
mol
kj
E = 2.22 V, AG = 429
mol
kj
O E = -2.22 V, AG = –429
mol
kj
E = -2.22 V, AG = 429
%3D
mol
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