Consider the following reaction with vanadium and iron: 2 Fe2+ (aq) + √2+ (aq) 2 Fe³+ (aq) + V(s) When this reaction reaches equilibrium, what will be the cell potential (V)? Fe3+ +eFe2+ E = +0.77 V2+ + 2e-V E = -0.49 (the answer should be entered with 3 DIGITS; do not enter units; give answer in normal notation--examples include 0.00 and 1.23 and 120. and -123 and 123. and 12.3) Question 5 of 32 Moving to another question will save this response. ^ & 3 6 7 9 56 Q @ W E 4 R % 5 T Y U * 8 1 O D
Consider the following reaction with vanadium and iron: 2 Fe2+ (aq) + √2+ (aq) 2 Fe³+ (aq) + V(s) When this reaction reaches equilibrium, what will be the cell potential (V)? Fe3+ +eFe2+ E = +0.77 V2+ + 2e-V E = -0.49 (the answer should be entered with 3 DIGITS; do not enter units; give answer in normal notation--examples include 0.00 and 1.23 and 120. and -123 and 123. and 12.3) Question 5 of 32 Moving to another question will save this response. ^ & 3 6 7 9 56 Q @ W E 4 R % 5 T Y U * 8 1 O D
General Chemistry - Standalone book (MindTap Course List)
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Chapter19: Electrochemistry
Section: Chapter Questions
Problem 19.127QP
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Consider the following reaction with vanadium and iron:
2 Fe2+ (aq) + V2+ (aq) → 2 Fe3+ (aq) + V(s)
When this reaction reaches equilibrium, what will be the cell potential (V)?
Fe3+ +eFe2+
E = +0.77
V2+ + 2e →V
E = -0.49
(the answer should be entered with 3 DIGITS; do not enter units; give answer in normal notation--examples include 0.00 and 1.23 and 120. and -123
and 123. and 12.3)
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