Calculate K, for each reaction. a. N204(8) = 2 NO2(8) b. N2(8) + 3 H2(8) = 2 NHa(8) c. N2(8) + O2(g) 2 NO(g) K. = 4.10 x 10-31 (at 298 K) K. = 5.9 x 10 (at 298 K) K. = 3.7 x 10° (at 298 K) %3D

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter14: Chemical Equilibrium
Section: Chapter Questions
Problem 14.23QE: Kc at 137 C is 4.42 for NO(g) + 12 Br2(g) NOBr(g) Calculate Kc at 137 C for 2NOBr(g) 2NO(g) +...
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Calculate K, for each reaction.
a. N204(8) = 2 NO2(8)
b. N2(8) + 3 H2(8) = 2 NHa(8)
c. N2(8) + O2(g) 2 NO(g) K. = 4.10 x 10-31 (at 298 K)
K. = 5.9 x 10 (at 298 K)
K. = 3.7 x 10° (at 298 K)
%3D
Transcribed Image Text:Calculate K, for each reaction. a. N204(8) = 2 NO2(8) b. N2(8) + 3 H2(8) = 2 NHa(8) c. N2(8) + O2(g) 2 NO(g) K. = 4.10 x 10-31 (at 298 K) K. = 5.9 x 10 (at 298 K) K. = 3.7 x 10° (at 298 K) %3D
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