Calculate the 4-week soil moisture flux in cm/day between based on the following data. You can use the table below for your summary of answer.
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- The section size of a water pipe is (100cm Χ 100cm), three types of soils A, B, and C are placed in the pipe, and a fixed amount of water is injected into the top left tap to keep the water head difference between the left and right ends of the pipe 60cm. The three soil permeability coefficients are k_A = 0.05 cm/sec , K_B = 0.1 cm/sec, k_C = 0.001 cm/sec, please calculate the following values:(1) The fixed amount of water injected into the faucet on the upper left (cm3/hr)(2) What is the total water head consumed by each of the three soils of A, B, and C (cm)(3) The overall volumetric seepage force of water flowing through the three soils (kN/m3)For a falling a head permeability test, the following data were recorded. Length of soil specimen = 500 mm. Area of soil specimen = 16 cm2 Area of stand pipe = 0.97 cm2 Head difference at time t =0 is 760 mm. Head difference at time t = 6min. is 410mm. The test was conducted at a temp. of 20 ֯C. with a unit wt. of water equal to 9.789 kN/m3 and the viscosity of water at 20 ֯C is 1.005 x 10-3 N.8/m2 . Compute the hydraulic conductivity of the soil. Compute the absolute permeability of the soil. What is the head difference at time t = 4 min?Calculate % Silt using the following values; a. Weight of soil= 50 g b. HR reading at 40 sec.= 25 c. Temp at 40 sec= 25 oCd. HR at 2 hrs= 16 e. Temp at 2 hrs= 26 * A. 17.28 B. 17.25 C 17.22 D. 17.19
- H2 = 0.3’ h = 1.25’ H1 = 0.2’ d = 1.5” H = 0.5’ D = 4” Ksand = 0.000075 ft/min Ksilt = 0.0038 ft/min Determine: Determine the total flow of water q. Find the equivalent permeability for the soil.A TDR probe of a length of 60 cm was installed vertically into a soil profile befor e seeding wheat in the spring. TDR reading on May 15 (beginning of the season) was L0 = 2.900 m ; L1=5.114 m. On the day of harvesting September 8 (end of the season), the reading was L0 =2.900 m and L1=4.331 m. Assume there is no rainfall, what was the total change in soil water storage in the root zone (60 cm depth)?41 The data from a falling head test is shown. Diameter of standpipe: 4 cm. Initial Head: 92.9 cm. Duration of test: 12 min. Length of soil sample: 33.27 cm. Diameter of permeameter: 43 cm. If the soil permeability is 0.0028 cm/min, determine the final head (in cm.) of the permeability test. Round off to two decimal places.
- A layer of silty soil of thickness 5 m lies below the ground surface at a particular site and below the silt layer lies a clay stratum. The ground water table is at a depth of 4 m below the ground surface.The following data are available for both the silt and clay layers of soil.Silt layer: ?10 = 0.018 mm, e = 0.7, and Gs = 2.7Clay layer: e = 0.8 and Gs = 2.75Required: (a) Height of capillary rise, (b) capillary pressure, (c) the effective pressure at the ground surface, at groundwater table (GWT) level, at the bottom of the silt layer and at a depth of H =6 m below ground level, and (d) at a depth 2 m below ground level. (Sketch or draw the stress distribution diagram).A layer of silty soil of thickness 5 m lies below the ground surface at a particular site and below thesilt layer lies a clay stratum. The ground water table is at a depth of 4 m below the ground surface.The following data are available for both the silt and clay layers of soil. Silt layer: ?10= 0.018 mm, e= 0.7, and Gs = 2.7Clay layer: e = 0.8 and Gs = 2.75Required: (a) Height of capillary rise, (b) capillarypressure, (c) the effective pressure at theground surface, at groundwater table (GWT)level, at the bottom of the silt layerand at a depth of H =6 m below groundlevel, (d) at a depth 2 m below ground level.(Sketch or draw the stress distribution diagram).For a falling head laboratory test, the following are the given values:• Length of soil specimen = 210.00 mm• Initial head = 523.00 mm• Final head = 297.00 mm• Duration of test = 3.50 mins• Area of standpipe = 42.0 sq.mm• Area of specimen = 1050.00 sq.mmA. Compute for the hydraulic conductivity of the soil in cm/sec.B. Determine the seepage velocity if n=0.35C. Determine the head difference at t = 120 sec
- GIVEN THE FOLLOWING FOR A SOIL SAMPLE: S=0.8 n=0.28 and Gs = 2.5 FIND THE MOIST UNIT WIEIGHT. USE yw = 9.81 KN/(m^3)Q- If a soil has a voids ratio of 0.68 and water percolating through it has a discharge velocity of 1.35*10-2cm/s. Calculate its seepage velocity.GIVEN THE FOLLOWING FOR A FULLY SATURATED SOIL: n=0.28 and Gs = 2.5 FIND THE WATER CONTENT. USE yw = 9.81 KN/(m^3). Use soil Mechanics