For the state of stresses (in MPa) shown in the figure below, the maximum shear stress (in MPa) is 2 4 4 2
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- Compare the engineering and true secant elastic moduli for the natural rubber in Example Problem 6.2 at an engineering strain of 6.0. Assume that the deformation is all elastic.For the following state of stress find the principal stresses.A state of stress is specified in the figure shown below. Determine the Normal stress σy (mPa) on the Principal Plane if P1 = -5 mPa; P2 = 39 mPa and v = 21 mPa
- At a creation point in a strained material, the principle stresses are 100N/mm2 and 40 N/mm2 both in tensile. Find normal, tangential and resultant stresses across a plane through the point at 480 to the major principal plane using Mohr's circle of stress.what differ between plane stress and strain.As like pancel is which of those? （eg,a pancil ,glass normal face or glass side face)The couple M acts in a vertical plane and is applied to a beam oriented as shown. Determine (a) the angle that the neutral axis forms with the horizontal plane, (b) the maximum tensile stress in the beam
- Find the lightest S-shape for the beam shown if the working stress in bending is 120 MPa. What is the maximum bending stress in the beam selected? Lightest S-shape beam =Maximum bending stress (MPa) =Answer the following true or false questions? 1. The thermal extension of any member depends on the expanslon coefficient of this member. 2. The ratio of stress to strain Is constant for any material. 3. In compound bars, the change in length does not depend on the position of applied load. 4. When the shear force Is zero, the bending moment is zero. 5. The bending stress on a beam depends on the radius of curvature of the beam. 6. The maximum lorslon stress occurs at the center of a shaft.A rigid bar AB is hinged at A and is supported by a rod CD at C. The rod is pin connected at D, as shown. Neglect deflections of the bar due to bending. Use E=200 GPa. If the allowable stress in rod CD is 120 MPa, what weight W in kgs can be safely applied?
- The stress concentration occurs whenever there is an abrupt change in the cross-section of a component or there is any discontinuity in the material. The figure given below shows a flat plate with a hole of diameter d. The plate is fixed at one end and the other end is subjected to a tensile load of P = 44 kN due to which there is a change in length of 0.4 mm. The thickness of the plate is 11.5 mm. The maximum stress developed in the flat plate is 228 MPa. Take Young's modulus(E) = 210 GPa and theoretical stress concentration factor =2, Calculate the following values: i) Width of the plate (W2) in mm ( ii) Nominal Stress in MPa ( iii) Diameter of the hole (d) in mmCalculate the value of the shear stress on the plane a-a as shown in the figure. Also, calculate the value of the principal stresses.The plastic tube is subjected to a torque of 150 N X m. Determine the average shear stress in the tube if the mean dimension a = 200 mm. Each side has a thickness of t = 3 mm. (The answer is 1.25 MPa)
