Calculate the amount of heat needed to convert 74.6g of water at 25°C to steam at 100°C. 7. q=(74.69)(4.1851g.06)(l00°C-25°C ) = 23387J -100 2= Huapamol q=(40.67 nsimol)(4.14 mol) =168.37 hJ=168373J 2 5°C 238873+1683735=191760J 1924s mYR Heat 9H2O -74.69 Rev2020 -4.14 mol HzO 18.0g/mol

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