Calculate the binding energy per nucleon for the 26 Fe nucleus. (Atomic masses: iron-56 = 55.9349 amu; hydrogen-1 = 1.0078 amu; mass of neutron = 1.0087 amu) HOW DO WE GET THERE? We must first calculate the mass defect (Am) for 56Fe. Since atomic masses (which include the electrons) are given, we must decide how to account for the electron mass: 55.9349 = mass of Fe atom = mass of nucleus + 26 me 1.0078 = mass of †H atom = mass of nucleus + me Thus, since a 56Fe nucleus is "synthesized" from 26 protons and 30 neutrons, we see that Am = (55.9349 - 26 me) - [26(1.0078 - me) + 30(1.0087)]. Solve for Am. Am = 56.4634 X amu
Calculate the binding energy per nucleon for the 26 Fe nucleus. (Atomic masses: iron-56 = 55.9349 amu; hydrogen-1 = 1.0078 amu; mass of neutron = 1.0087 amu) HOW DO WE GET THERE? We must first calculate the mass defect (Am) for 56Fe. Since atomic masses (which include the electrons) are given, we must decide how to account for the electron mass: 55.9349 = mass of Fe atom = mass of nucleus + 26 me 1.0078 = mass of †H atom = mass of nucleus + me Thus, since a 56Fe nucleus is "synthesized" from 26 protons and 30 neutrons, we see that Am = (55.9349 - 26 me) - [26(1.0078 - me) + 30(1.0087)]. Solve for Am. Am = 56.4634 X amu
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter18: Nuclear Chemistry
Section: Chapter Questions
Problem 5SP
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![INTERACTIVE EXAMPLE Nuclear Binding Energy II
Calculate the binding energy per nucleon for the
Fe
nucleus. (Atomic masses: iron-56 = 55.9349 amu; hydrogen-1 = 1.0078 amu; mass of neutron = 1.0087 amu)
HOW DO WE GET THERE?
We must first calculate the mass defect (Am) for 56Fe. Since atomic masses (which include the electrons) are given, we must decide how to
account for the electron mass:
55.9349 = mass of Fe atom = mass of nucleus + 26 me
1.0078 = mass of H atom = mass of nucleus + m.
Thus, since a 56Fe nucleus is "synthesized" from 26 protons and 30 neutrons, we see that Am = (55.9349 - 26 m.) - [26(1.0078 - me) +
30(1.0087)].
Solve for Am.
Am = 56.4634
amu](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd5a5cd4a-ee8a-485c-8cb2-f3ca89309b2b%2Fdfb3daa9-5d0d-481d-9e1c-47891317947e%2F2ggqfhr_processed.png&w=3840&q=75)
Transcribed Image Text:INTERACTIVE EXAMPLE Nuclear Binding Energy II
Calculate the binding energy per nucleon for the
Fe
nucleus. (Atomic masses: iron-56 = 55.9349 amu; hydrogen-1 = 1.0078 amu; mass of neutron = 1.0087 amu)
HOW DO WE GET THERE?
We must first calculate the mass defect (Am) for 56Fe. Since atomic masses (which include the electrons) are given, we must decide how to
account for the electron mass:
55.9349 = mass of Fe atom = mass of nucleus + 26 me
1.0078 = mass of H atom = mass of nucleus + m.
Thus, since a 56Fe nucleus is "synthesized" from 26 protons and 30 neutrons, we see that Am = (55.9349 - 26 m.) - [26(1.0078 - me) +
30(1.0087)].
Solve for Am.
Am = 56.4634
amu
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