Answered: Calculate the diameter of a 3.15 cm…

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter23: Series And Parallel Circuits

Section: Chapter Questions

Problem 44A

See similar textbooks

Related questions

Concept explainers

Question

Calculate the diameter of a 3.15 cm long tungsten filament in a lightbulb if its resistance is 0.341 Ω. (The resistivity of tungsten is 5.60×10^-8 Ωm.)

Expert Solution

Step 1

When current flows through a conductor then the opposition offered by the conductor to the current is termed as its resistance.

The formula to calculate the resistance is given by

$R = ρ \frac{l}{A}$

where $ρ$ is the resistivity of the filament, $A$ is the cross-sectional area of the filament and $l$ is the length of it.

Again the formula to calculate the cross sectional area is given by

$A = π r^{2}$ where $r$ is radius of the circuit.

Substitute this expression into the formula of the resistance and then rearrange to find an expression for the radius.

$R = ρ \frac{l}{π r^{2}} r^{2} = \frac{ρ l}{π R} r = \sqrt{\frac{ρ l}{π R}}$

Trending now

This is a popular solution!

Step by step

Solved in 4 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions