Calculate the enthalpy of the following reaction: HCI + NaOH Nacl + H,0 AH HCI- -92.3 kJ/mol NAOH= -426.7 kJ/mol NaCl= -411 kJ/mol H20= -286 kl/mol Reaction: ΔΗ+ kJ/mol
Calculate the enthalpy of the following reaction: HCI + NaOH Nacl + H,0 AH HCI- -92.3 kJ/mol NAOH= -426.7 kJ/mol NaCl= -411 kJ/mol H20= -286 kl/mol Reaction: ΔΗ+ kJ/mol
Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter5: Thermochemistry
Section: Chapter Questions
Problem 80E: Ethanol, C2H5OH, is used as a fuel for motor vehicles, particularly in Brazil. (a) Write the...
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