Question
Asked Aug 7, 2019
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Calculate the equilibrium constant for the following reaction at 25o C, given that change in standard Gibbs free energy (f) of O3 (g) is 163.4 kJ/mol.

2O3(g)  -> 3O2(g)

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Expert Answer

Step 1

Given:

The free energy change is 163.4 kJ/mol.

Temperature = 250C = 25 + 273 K = 298 K.

 

Step 2

The relation between free energy change and equilibrium constant is:

Where

R = gas constant =8.314 J /mol K.

T = temperature.

K = equilibrium constant.

ln K = log of K (base e).

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AG -RTlnK

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Step 3

Let us put the values in the equation as:

Free energy cha...

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Science

Chemistry

Equilibrium Concepts

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