Calculate the following for each run: the initial molarities of I- and H2O2 (from the solutions tables) the rates of reaction [I2]/time (calculate the [I2] from [S2O32-] and the reaction: I2(aq) + 2 S2O32-(aq) → 2I-(aq) + S4O62-(aq) Choose the correct rate law for this reaction from your calculations.
Calculate the following for each run: the initial molarities of I- and H2O2 (from the solutions tables) the rates of reaction [I2]/time (calculate the [I2] from [S2O32-] and the reaction: I2(aq) + 2 S2O32-(aq) → 2I-(aq) + S4O62-(aq) Choose the correct rate law for this reaction from your calculations.
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter10: Fuels, Organic Chemicals, And Polymers
Section: Chapter Questions
Problem 119QRT
Related questions
Question
Given the following:
Solutions | Flask 1 | Flask 2 | Flask 3 |
0.04 M KI | 25.0 mL | 25.0 mL | 12.5 mL |
1% starch | 5.00mL | 5.00mL | 5.00mL |
0.03 M Na2S2O3 | 5.50 mL | 5.50 mL | 5.50 mL |
0.05 M H2SO4 | 5.00 mL | 5.00mL | 5.00mL |
0.08 M NaCl | 0 | 0 | 10.0 mL |
and
Solutions | Beaker 1 | Beaker 2 | Beaker 3 |
0.04 M H2O2 | 25.0 mL | 12.5 mL | 25.0 mL |
deioinized water | 0 | 12.5 mL | 0 |
Following the procedure Run 1 is when Beaker 1 is added to Flask 1 and the timer is started giving the time recorded for the run in the table below. This is repeated with Beaker 2 and Flask 2 for Run 2 and finally Beaker 3 and Flask 3 for Run 3:
The results for these runs are given below:
Run | Time (seconds) |
1 | 35 |
2 | 66 |
3 | 72 |
Calculate the following for each run:
- the initial molarities of I- and H2O2 (from the solutions tables)
- the
rates of reaction [I2]/time (calculate the [I2] from [S2O32-] and the reaction:
I2(aq) + 2 S2O32-(aq) → 2I-(aq) + S4O62-(aq)
Choose the correct rate law for this reaction from your calculations.
Group of answer choices
Rate=k[I-][H2O2]
Rate=k{I-]2[H2O2]
Rate=k[I-][H2O2]2
Rate=k[I-]2[H2O2]2
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 4 steps
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Recommended textbooks for you
Chemistry: The Molecular Science
Chemistry
ISBN:
9781285199047
Author:
John W. Moore, Conrad L. Stanitski
Publisher:
Cengage Learning
Chemistry: The Molecular Science
Chemistry
ISBN:
9781285199047
Author:
John W. Moore, Conrad L. Stanitski
Publisher:
Cengage Learning