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ChemistryQ&A LibraryIn a solution containing 25ml (NH4)2S2O8 with a total volume = 100 ml =0.1 liters , the solution composition are shown below.Note; the solution require 25ml of 0.2M S2O8^-2.SOLUTION Kl KNO3 EDTA Na2S2O3 STARCH50ml 23ml 1 drop 1 ml 10 dropsExperiment; initial (S2O8-2) =0.05M ; INITIAL (l-)=0.10 Mml of S2O3^-2 added Time in minutes and seconds for color change Cumulative time in seconds Total moles of S2O8^-2 consumed1 1:43 2.0 x 10^-42 1:20 4.0 x 10^-43 1:13 6.0 x 10 ^-44 1.17 8.0 x 10 ^-45 1.24 10 x 10 ^-41a) Find the cumulative time in secondsb) for the runs ,plot mole of S2O8^2- REACTION vs. time in seconds2) Draw a straight line through ( origin ) the points and calculate the slope3) divide the value of the slope by the total volume of ( 0.1 L) to get the rate in units of M/s4) find the rate5 )calculate x and y and kStart your trial now! First week only $4.99!*arrow_forward*

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In a solution containing 25ml (NH4)2S2O8 with a total volume = 100 ml =0.1 liters , the solution composition are shown below.

Note; the solution require 25ml of 0.2M S2O8^-2.

SOLUTION Kl KNO3 EDTA Na2S2O3 STARCH

50ml 23ml 1 drop 1 ml 10 drops

Experiment; initial (S2O8-2) =0.05M ; INITIAL (l-)=0.10 M

ml of S2O3^-2 added Time in minutes and seconds for color change Cumulative time in seconds Total moles of S2O8^-2 consumed

1 1:43 2.0 x 10^-4

2 1:20 4.0 x 10^-4

3 1:13 6.0 x 10 ^-4

4 1.17 8.0 x 10 ^-4

5 1.24 10 x 10 ^-4

1a) Find the cumulative time in seconds

b) for the runs ,plot mole of S2O8^2- REACTION vs. time in seconds

2) Draw a straight line through ( origin ) the points and calculate the slope

3) divide the value of the slope by the total volume of ( 0.1 L) to get the rate in units of M/s

4) find the rate

5 )calculate x and y and k

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