Calculate the heat of reaction, AHrxn, for the combustion of one mole of C6H6(1) using the reactions provided below. 6 C(s, graphite) + 3 H2(g) → C6H6(1) H2(g) + ½ O2(g) → H2O(I) AH = -285.8 kJ C(s, graphite) + O2(g) → CO2(g) AH = 49.0 kJ %3D AH = -393.5 kJ

Chemistry: Principles and Practice
3rd Edition
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Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
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Chapter5: Thermochemistry
Section: Chapter Questions
Problem 5.34QE
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Calculate the heat of reaction, Hrxn, for the combustion of one mole of C6H6(l) using the ∆reactions provided below.

6 C(s, graphite) + 3 H2(g) → C6H6(l)     ∆H = 49.0 kJ

H2(g) + ½ O2(g) → H2O(l)                     ∆H = -285.8 kJ∆

C(s, graphite) + O2(g) → CO2(g)             ∆H = -393.5 kJ

 

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4. Calculate the heat of reaction, AHrxn, for the combustion of one mole of C6H6(1) using the
reactions provided below.
6 C(s, graphite) + 3 H2(g) → C6H6(1)
H2(g) + ½ O2(g) → H2O(I) AH = -285.8 kJ
C(s, graphite) + O2(g) → CO2(g)
AH = 49.0 kJ
%3D
AH = -393.5 kJ
Transcribed Image Text:4. Calculate the heat of reaction, AHrxn, for the combustion of one mole of C6H6(1) using the reactions provided below. 6 C(s, graphite) + 3 H2(g) → C6H6(1) H2(g) + ½ O2(g) → H2O(I) AH = -285.8 kJ C(s, graphite) + O2(g) → CO2(g) AH = 49.0 kJ %3D AH = -393.5 kJ
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