Teacher stated that there should only be one final answer using two decimal places, not three answers. Calculate the heat released (in kJ) when 520.59 grams of benzene (C6H6) are cooled from 114.9° C to 2.0°C.AHvap= 33.8 kJ/molAH fus= 10.9 kJ/molBoiling Point = 80.1°CMelting Point= 5.5°CCsp(1) = 1.70 J/g°CCsp(s)= 1.51 J/g°CCsp(g)= 1.05 J/g°CEnter your answer using 2 decimal places ABBREVIATIONS AND SYMBOLSCONSTANTS & CONVERSIONSmolar massMamount of substanceatmosphereatomic mass unitgas constantRnmolemolR= 8.314 J•mol-1·K-'gPlanck's constanthatmgramhourR= 0.0821 L·atm•mol-l·K-'huatomic molar massAjouleJpressurePNA = 6.022 × 1023 mol-'kelvinKsecondAvogadro constantCelsius temperature|centi- prefixenergy of activationenthalpyfrequencyNAh= 6.626 × 10-34 J-s°Ckilo- prefixkspeed of lightliterLtemperature, KT.c = 2.998 × 10® m·s-'Eameasure of pressure mmHgtime0 °C = 273.15 K1 atm = 760 mmHgHmilli- prefixvolumeVmmolarM1 atm = 760 torrEQUATIONSq = MC¸ATc = AvPV = nRTAE = q +wE = hvPERIODIC TABLE OF THE ELEMENTS11812HНе1.008213141516174.00346.79.10LiВеВFNe6.9419.01210.8112.0114.0116.0019,0020.181112131415161718NaMgSiAl26.98S32.07CIAr22.9924.31347910111230.973328.0935.4539.9519202122232425Mn26272829303132343536KСаScTiVCrFeCoNiCuZnGa69.72GeAsSeBrKr39.1040.0844.9647.8850.9452.0054.9455.8558.9358.6963,5565.3972.6174.9278.9679.9083.80373839404142434445464748495051525354RbSrYZrNbМоTcRuRhPdInAg107.9CdSnSbТеIХе85.4787.6288.9191.2292.9195.94101.1102.9106.4112,4114.8118.7121.8127.6126.9131.3555657727374757677787980818283848586CsВаLaHfТаWReOsIrPtAuHgTIPbBiPoAtRn132,9137.3138.9178.5180.9183.8186.2190.2192.2195.1197.0200,6204.4207.2209.0878889104105106107108109110111112113114115116117118FrRaAcRfDbSgBhHsMtDsRgCnNhF1McLvTsOg5859606162636465666768697071СеPrNdPmSmEuGdTbDyНоErTmYbLu140,1140.9144.2150.4152.0157.3158.9162,5164,9167.3168,9173,0175,0EB90919293949596979899100101102103ThРаUNpPuAmCmBkCfEsFmMdNoLr232.0231.0238.0

Given: Mass of benzene = 520.59 g. Initial temperature of benzene = 114.9 oC And final temperature…

Calculate the heat released (in kJ) when 520.59 grams of benzene (C,H6) are cooled from 114.9°C to 2.0°C. AHvap= 33.8 kJ/mol %3D ΔΗu = 10.9 kJ/mol Boiling Point = 80.1°C Melting Point= 5.5°C Csp(1) = 1.70 J/g° c %3D Csp(s)= 1.51 J/g°C Csp(g)= 1.05 J/g°C Enter your answer using 2 decimal places

Calculate the heat released (in kJ) when 520.59 grams of benzene (C,H6) are cooled from 114.9°C to 2.0°C. AHvap= 33.8 kJ/mol %3D ΔΗu = 10.9 kJ/mol Boiling Point = 80.1°C Melting Point= 5.5°C Csp(1) = 1.70 J/g° c %3D Csp(s)= 1.51 J/g°C Csp(g)= 1.05 J/g°C Enter your answer using 2 decimal places

Chemistry: Principles and Practice

3rd Edition

ISBN:9780534420123

Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Chapter5: Thermochemistry

Section: Chapter Questions

Problem 5.24QE

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