Methanol undergoes combustion according to the equation. Find the amount of heat given off from the combustion of 64 g CH3OH (methanol). (MM = 32 g/mol) (∆H=-1452.8 kJ) 2 CH3OH(l) + 3 O2(g) ->  2 CO2(g) + 4 H2O(l) a. 726.4 kJ b. -1452.8 kJ c. -2179.2 kJ c. -2905.6 kJ

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