Calculate the missing value ** and use tables to approximate the value of ***.Using a 1% level of significance, state the decision criteria for this test State the conclusion for the test and why Mrs. Paul wants to test that claim that, on average, her students average mark is 85. She pulls therecords of 100 of per past students over a three-year period. The grades inputted into MINITABfor analysis. Exhibit 1 below shows the results of an analysis carried out on the data obtained.Exhibit 1One-Sample Z: Level I/IITest of mu85 vs mu not85The assumed sigma = 15.0VariableNМeanStDevSE MeanPStudents Score10075.412.99*****

We have given that. We have given that Sample size n =100 Sample mean =75.4 Standard deviation =15

Calculate the missing value ** and use tables to approximate the value of ***. Using a 1% level of significance, state the decision criteria for this test State the conclusion for the test and why

Calculate the missing value and use tables to approximate the value of *. Using a 1% level of significance, state the decision criteria for this test State the conclusion for the test and why

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Let ?1 denote true average tread life for a premium brand of P205/65R15 radial tire, and let ?2 denote the true average tread life for an economy brand of the same size. Test H0: ?1 − ?2 = 5000 versus Ha: ?1 − ?2 > 5000 at level 0.01, using the following data: m = 45, x = 42,100, s1 = 2400, n = 45, y = 36,200, and s2 = 1800.Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) z = P-value = State the conclusion in the problem context. Fail to reject H0. The data does not suggest that the difference in average tread life exceeds 5000.Reject H0. The data suggests that the difference in average tread life exceeds 5000. Fail to reject H0. The data suggests that the difference in average tread life exceeds 5000.Reject H0. The data does not suggest that the difference in average tread life exceeds 5000.
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Mrs. Paul wants to test that claim that, on average, her students average mark is 85. She pulls therecords of 100 of per past students over a three-year period. The grades inputted into MINITABfor analysis. Exhibit 1 below shows the results of an analysis carried out on the data obtained. Exhibit 1 One-Sample Z: Level I/IITest of mu = 85 vs mu not = 85The assumed sigma = 15.0 Variable N Mean StDev SEMean Z PStudents Score 100 75.4 12.99 * ** *** i. Calculate the SEMean ii. Construct a 98% confidence interval for the population scores of Mrs. Paul’s students.iii. State the null and alternate hypothesis for this test. iv. Calculate the missing value ** and use tables to approximate the value of ***.v. Using a 1% level of significance, state the decision criteria for this test…
Mrs. Paul wants to test that claim that, on average, her students average mark is 85. She pulls therecords of 100 of per past students over a three-year period. The grades inputted into MINITABfor analysis. Exhibit 1 below shows the results of an analysis carried out on the data obtained.Exhibit 1One-Sample Z: Level I/IITest of mu = 85 vs mu not = 85The assumed sigma = 15.0 Variable N Mean StDev SE Mean Z P Students Score 100 75.4 12.99 * ** ***i. Calculate the SEMeanii. Construct a 98% confidence interval for the population scores of Mrs. Paul’s students.iii. State the null and alternate hypothesis for this test.iv. Calculate the missing value ** and use tables to approximate the value of ***v. Using a 1% level of significance, state the decision criteria for this test vi. State the conclusion for the test and why
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