Calculate the molarity of 15.4 g of sucrose (C12H22011) in 74.0 mL of solution,[Molar mass of C12H22011 = 342.3 g/mol]%3DNote: Answers must be numeric, not alphanumeric-42, not forty-two. Describe how you would prepare 750 mL of a 0.707 M NANO3 solution.Strategy: How many grams of NaNO3 does 250 mL of a 0.707 M solution contain?[Molar mass (NANO:) = 85.00 g/mol.]Note: Answers must be numeric, not alphanumeric-42, not forty-two.

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Calculate the molarity of 15.4 g of sucrose (C12H22011) in 74.0 mL of solution, [Molar mass of C12H22011 = 342.3 g/mol] %3D Note: Answers must be numeric, not alphanumeric-42, not forty-two.

Introductory Chemistry: A Foundation

8th Edition

ISBN:9781285199030

Author:Steven S. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Donald J. DeCoste

Chapter15: Solutions

Section: Chapter Questions

Problem 30QAP

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Concept explainers

Solutions

Solutions can be considered as homogeneous mixtures which contain two or more than two chemical substances. The chemical substance which is the greater part is defined as solvent. And the chemical substance that is dissolved in a solvent is referred to as solute. Solution chemistry plays an important role in chemistry since it supports many commercial applications of solutions.

Question

Calculate the molarity of 15.4 g of sucrose (C12H22011) in 74.0 mL of solution,
[Molar mass of C12H22011 = 342.3 g/mol]
%3D
Note: Answers must be numeric, not alphanumeric-42, not forty-two.

Describe how you would prepare 750 mL of a 0.707 M NANO3 solution.
Strategy: How many grams of NaNO3 does 250 mL of a 0.707 M solution contain?
[Molar mass (NANO:) = 85.00 g/mol.]
Note: Answers must be numeric, not alphanumeric-42, not forty-two.

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