Solubility Product Constant128Identity of Oxalate Salt:SrC204. Hz0molarmass :87.62of st e 204- Hao12. or0.00433g Sr (204- H20l00 g t20Ksp from Solubility (Show your calculations below) 5.0016. 00 K 4Solubility:18. 01193. 659imolcenvert +CX100.004 33g src2 04molesH20: 2. 2 359 x10mot193. 65 dimolcaloulateMolartry2. 2359 x10"-44mol: 2.2359 x10Mmoi2.2359 x 101000 DA100 mStca04. H20 ? srat+ cr2042-ksp: [ 2.23 59 x10m]atorarconcentrutren of both si²* a cra oy-- 2. 23 59 xic-4m= 4.9996x10- 8Mnou- 8ksP = 5. 00 x10Calculate the molarity of KMnO4 solution needed to titrate 50.00 mL of a saturatedsolution of this oxalate salt. It should take 7.50 mL of KMnO4 solution to titrate thesaturated oxalate solution.Prie.dMolarity:Instructor Approval:L OI

To Calculate the Molarity of KMNO4 needed for the titration.

Answered: Calculate the molarity of KMNO4…

Calculate the molarity of KMNO4 solution needed to titrate 50.00 mL of a saturated solution of this oxalate salt. It should take 7.50 mL of KMnO4 solution to titrate the saturated oxalate solution.

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter7: Statistical Data Treatment And Evaluation

Section: Chapter Questions

Problem 7.10QAP

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Question

Solubility Product Constant
128
Identity of Oxalate Salt:
SrC204. Hz0
molar
mass :
87.62
of st e 204- Hao
12. or
0.00433g Sr (204- H20
l00 g t20
Ksp from Solubility (Show your calculations below) 5.00
16. 00 K 4
Solubility:
18. 01
193. 659imol
cenvert +C
X10
0.004 33g src2 04
moles
H20
: 2. 2 359 x10
mot
193. 65 dimol
caloulate
Molartry
2. 2359 x10"
-44
mol: 2.2359 x10M
moi
2.2359 x 10
1000 DA
100 m
Stca04. H20 ? srat
+ cr2042-
ksp: [ 2.23 59 x10m]
atorar
concentrutren of both si²* a cra oy-
- 2. 23 59 xic-4m
= 4.9996x10- 8
Mnou
- 8
ksP = 5. 00 x10
Calculate the molarity of KMnO4 solution needed to titrate 50.00 mL of a saturated
solution of this oxalate salt. It should take 7.50 mL of KMnO4 solution to titrate the
saturated oxalate solution.
Prie.d
Molarity:
Instructor Approval:
L OI

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