How many liters of a 5.00 M solution of Na3PO4 are needed to have 4.00 equivalents ?First we need the equation for dissolving the salt, Na3PO43 Na+1 + PO43An equivalent is a mole of charges, either + or -, but not both, they are not addedthe conversion factor is 1 mol =eqFirst convert equivalents into moles1 moleq(-%3DmoleqThen calculate the liters1Lmol)(----) =molа. 0.00b. 1.00с. 2.00d. 3.00е. 4.00.00g. 6.00h.00i. 10.00j. 2000k. 102I. 103m. 106n. 109О. 1012р. 1029. 10-3r. 10-6S. 10-9t. 10-12u. 108v. 10-1w. 101Х. 30.0у. О.100z. 0.200аа. 20.0bb. 40.0СС. 1.33dd. 0.267

Here we are required to find volume required to prepare 5 M of sodium phosphate

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How many liters of a 5.00 M solution of Na3PO4 are needed to have 4.00 equivalents ?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter4: Types Of Chemical Reactions And Solution Stoichiometry

Section: Chapter Questions

Problem 47E

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Concept explainers

Solutions

Solutions can be considered as homogeneous mixtures which contain two or more than two chemical substances. The chemical substance which is the greater part is defined as solvent. And the chemical substance that is dissolved in a solvent is referred to as solute. Solution chemistry plays an important role in chemistry since it supports many commercial applications of solutions.

Question

How many liters of a 5.00 M solution of Na3PO4 are needed to have 4.00 equivalents ?
First we need the equation for dissolving the salt, Na3PO4
3 Na+1 + PO43
An equivalent is a mole of charges, either + or -, but not both, they are not added
the conversion factor is 1 mol =
eq
First convert equivalents into moles
1 mol
eq(-
%3D
mol
eq
Then calculate the liters
1L
mol)(--
--) =
mol
а. 0.00
b. 1.00
с. 2.00
d. 3.00
е. 4.00
.00
g. 6.00
h.
00
i. 10.00
j. 2000
k. 102
I. 103
m. 106
n. 109
О. 1012
р. 102
9. 10-3
r. 10-6
S. 10-9
t. 10-12
u. 108
v. 10-1
w. 101
Х. 30.0
у. О.100
z. 0.200
аа. 20.0
bb. 40.0
СС. 1.33
dd. 0.267

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