Calculate the number of kilowatt-hours of electricity required to produce 1.0 x 103 kg of aluminum by electrolysis of Al* if the applied voltage is 4.50 V and the process is 45% efficient. (1 kWh = 3.6 x10° J and 1 J = 1C x 1V)

Chemistry: Principles and Reactions
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Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter17: Electrochemistry
Section: Chapter Questions
Problem 88QAP: Consider the electrolysis of NiCl2 to Ni(s) and Cl2(g). (a) What is the minimum voltage required to...
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i.
Calculate the number of kilowatt-hours of electricity required to produce 1.0 x 103
kg of aluminum by electrolysis of Al* if the applied voltage is 4.50 V and the
process is 45% efficient. (1 kWh = 3.6 x10® J and 1 J = 1C x 1V)
ii.
Disproportionation reaction is an oxidation-reduction reaction in which the same
substance is oxidized and reduced. Complete and balance the following
disproportionation reaction.
Cl, (aq)
Cr (aq) + CIO (aq)
(basic solution)
Transcribed Image Text:i. Calculate the number of kilowatt-hours of electricity required to produce 1.0 x 103 kg of aluminum by electrolysis of Al* if the applied voltage is 4.50 V and the process is 45% efficient. (1 kWh = 3.6 x10® J and 1 J = 1C x 1V) ii. Disproportionation reaction is an oxidation-reduction reaction in which the same substance is oxidized and reduced. Complete and balance the following disproportionation reaction. Cl, (aq) Cr (aq) + CIO (aq) (basic solution)
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