Calculate the number of nitrogen atoms in 25.0 micrograms of aspartame, C14H18N2O5. 2.56 x1016 atoms O 3.01 x1019 atoms O 8.86 x1021 atoms O 1.02 x 1017 atoms O 5.11 x1016 atoms

Introductory Chemistry: A Foundation
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Chapter8: Chemical Composition
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Problem 117AP: alculate the number of moles of hydrogen atoms present in each of the following samples. l type='a'>...
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Calculate the number of nitrogen atoms in 25.0 micrograms of aspartame, C14H18N2O5.
2.56 x1016 atoms
O 3.01 x1019 atoms
O 8.86 x1021 atoms
O 1.02 x 1017 atoms
O 5.11 x1016 atoms
Transcribed Image Text:Calculate the number of nitrogen atoms in 25.0 micrograms of aspartame, C14H18N2O5. 2.56 x1016 atoms O 3.01 x1019 atoms O 8.86 x1021 atoms O 1.02 x 1017 atoms O 5.11 x1016 atoms
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