Asked Aug 30, 2019

Calculate the osmotic pressure of a 0.189 M aqueous solution of sucrose, C12H22O11, at 37 °C.


Expert Answer

Step 1

Colligative properties are the properties which depend on the number of atoms or molecules or ions or particles present in the solution. Some common colligative properties are depression in freezing point, elevation in boiling point, osmotic pressure and relative lowering in vapor pressure.


Step 2

Osmotic pressure is a colligative property that can be calculated with the help of concentration of solution. The relation between osmotic pressure and concentration of solution can be written as:


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Osmotic pressure = C x R x T Here concentration of solution (mol /L) C T Temperature (K) Universal gas constant (0.0821 L.atm/mol.K) R

Step 3

Calculate osmotic pressure for the given concentration of solution. 

C = 0.189 M

T = 37 °C =...


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Osmotic pressure = C x R x T 0.189 mol/L x 0.0821 L.atm/mol.K x 310.15 K = 4.81 atm


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