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Social ScienceWhen 0.713 grams of a protein were dissolved in 72.5 mL of solution at 28.5 degrees C, the osmotic pressure was found to be 35.6 torr. Calculate the molar mass of the protein.
When 0.713 grams of a protein were dissolved in 72.5 mL of solution at 28.5 degrees C, the osmotic pressure was found to be 35.6 torr. Calculate the molar mass of the protein.
Expert Answer
Osmotic pressure is an colligative property meaning it depends upon the amount of solute or ions present in solution.
Given here,
0.713 grams of a protein
dissolved in 72.5 mL (0.0725 L) of solution
[1 ml = 0.001 L]
at Temperature (T) = 28.5 degrees C + 273 = 301.5 K
the osmotic pressure found = 35.6 torr
convert torr to atm
conversion factor, 1 atm = 760 torr
So, osmotic pressure = 35.6 torr x (1 atm/760 torr) = 0.047 atm
R = 0.0821 L.atm/K.mol
M = molarity of solution
Using,
osmotic pressure = MRT
So,
0.047 = M x 0.0821 x 301.5
Molarity of solution = 0.002 M
With, molarity = moles/Liter of solution
w...
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