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When 0.713 grams of a protein were dissolved in 72.5 mL of solution at 28.5 degrees C, the osmotic pressure was found to be 35.6 torr. Calculate the molar mass of the protein.

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Osmotic pressure is an colligative property meaning it depends upon the amount of solute or ions present in solution.

Given here,0.713 grams of a proteindissolved in 72.5 mL (0.0725 L) of solution[1 ml = 0.001 L]at Temperature (T) = 28.5 degrees C + 273 = 301.5 Kthe osmotic pressure found = 35.6 torrconvert torr to atmconversion factor, 1 atm = 760 torrSo, osmotic pressure = 35.6 torr x (1 atm/760 torr) = 0.047 atmR = 0.0821 L.atm/K.molM = molarity of solutionUsing,osmotic pressure = MRTSo,0.047 = M x 0.0821 x 301.5Molarity of solution = 0.002 MWith, molarity = moles/Liter of solutionw...

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When 0.713 grams of a protein were dissolved in 72.5 mL of solution at 28.5 degrees C, the osmotic pressure was found to be 35.6 torr. Calculate the molar mass of the protein.

When 0.713 grams of a protein were dissolved in 72.5 mL of solution at 28.5 degrees C, the osmotic pressure was found to be 35.6 torr. Calculate the molar mass of the protein.

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