Calculate the percent composition of each element in C10H8 (molar mass = 128.171 amu)O %C = 93.7084% ; %H = 6.29122%%C = 7.87653% ; %H = 92.12347%%C = 6.29122% ; %H = 93.7084%O %C = 92.12347% ; %H =7.87653% QUESTION 2How many mL of a 1.2 M AICI3 solution would be needed to prepare 600 mL of a 0.48 M solution? (The following equation may behelpful: C1V1 = C2V2 ).O 225 mLO 240 mLO 17 mLO 16 mL

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Calculate the percent composition of each element in C10H8 (molar mass = 128.171 amu) %3D O %C = 93.7084% ; %H = 6.29122% %3D %3D %C = 7.87653% ; %H = 92.12347% %3D O %C = 6.29122% ; %H = 93.7084% %3D %3D O %C = 92.12347% ; %H =7.87653% %3D

Calculate the percent composition of each element in C10H8 (molar mass = 128.171 amu) %3D O %C = 93.7084% ; %H = 6.29122% %3D %3D %C = 7.87653% ; %H = 92.12347% %3D O %C = 6.29122% ; %H = 93.7084% %3D %3D O %C = 92.12347% ; %H =7.87653% %3D

Introductory Chemistry For Today

8th Edition

ISBN:9781285644561

Author:Seager

Publisher:Seager

Chapter7: Solutions And Colloids

Section: Chapter Questions

Problem 7.108E

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Concept explainers

Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.

Question

Calculate the percent composition of each element in C10H8 (molar mass = 128.171 amu)
O %C = 93.7084% ; %H = 6.29122%
%C = 7.87653% ; %H = 92.12347%
%C = 6.29122% ; %H = 93.7084%
O %C = 92.12347% ; %H =7.87653%

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