Calculate the pH for each case in the titration of 50.0 mL of 0.110 M HClO(aq)0.110 M HClO(aq) with 0.110 M KOH(aq).0.110 M KOH(aq). pka = 7.40 ka= 4.0*10^-8 What is the pH after addition of 50.0 mL KOH? What is the pH after addition of 60.0 mL KOH?

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