Calculate the pH of 0.1 M NaHC2O4. Your solution should involve a system of equations that simultaneously describes the dissociation of HC2O4- and formation of H+, H2C2O4, and C2O42-.

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Calculate the pH of 0.1 M NaHC2O4. Your solution should involve a system of equations that simultaneously describes the dissociation of HC2O4- and formation of H+, H2C2O4, and C2O42-.

Oxalic acid (H₂C2O4) is a diprotic acid, meaning that a single H₂C2O4 molecule can dissociate twice following the equilibrium
reactions presented by Equations 2.1 to 2.2.
H₂C₂O4 (aq) → H¹+ (aq) + HC₂O4 (aq)
(2.1)
(2.2)
HC₂04 (aq) → H+ (aq) + C₂0² (aq)
The acid dissociation constants (equilibrium constants) of the reactions are K₁₁=5.4 x 10-² and K₁2 = 5.2 × 10-5,
respectively. The acid dissociation constants are related to the molar concentrations of each ion by Equations 2.3 and 2.4.
Ка1
[H*][HC,O4]
[H₂C₂04]
(2.3)
[H+][C₂0²-]
[HC₂04]
(2.4)
Kaz
=
Transcribed Image Text:Oxalic acid (H₂C2O4) is a diprotic acid, meaning that a single H₂C2O4 molecule can dissociate twice following the equilibrium reactions presented by Equations 2.1 to 2.2. H₂C₂O4 (aq) → H¹+ (aq) + HC₂O4 (aq) (2.1) (2.2) HC₂04 (aq) → H+ (aq) + C₂0² (aq) The acid dissociation constants (equilibrium constants) of the reactions are K₁₁=5.4 x 10-² and K₁2 = 5.2 × 10-5, respectively. The acid dissociation constants are related to the molar concentrations of each ion by Equations 2.3 and 2.4. Ка1 [H*][HC,O4] [H₂C₂04] (2.3) [H+][C₂0²-] [HC₂04] (2.4) Kaz =
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