Calculate the pH of a 0.01M solution of salicylic acid (K₂ = 1.06 x 10-3 at 25 °C) using both the approximate and the exact quadratic equations. a

Fundamentals Of Analytical Chemistry
9th Edition
ISBN:9781285640686
Author:Skoog
Publisher:Skoog
Chapter21: Potentiometry
Section: Chapter Questions
Problem 21.9QAP
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Calculate the pH of a 0.01M solution of salicylic
acid (K₂ = 1.06 x 10-³ at 25 °C) using both the
approximate and the exact quadratic equations.
[H₂0²] = - ka + √ka² +4K a Ca
106X10-3
+
2
(1+06x10-3³ ) ² + 4 (1.06 × 10-3) (a
2
0.2059
Transcribed Image Text:Calculate the pH of a 0.01M solution of salicylic acid (K₂ = 1.06 x 10-³ at 25 °C) using both the approximate and the exact quadratic equations. [H₂0²] = - ka + √ka² +4K a Ca 106X10-3 + 2 (1+06x10-3³ ) ² + 4 (1.06 × 10-3) (a 2 0.2059
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