Calculate the pH of a 0.295 M solution of ethylenediamine (H2NCH,CH,NH2). The pKa values for the acidic form of ethylenediamine (HNCH, CH, NH) are 6.848 (pKa1) and 9.928 (pKa2). pH = Calculate the concentration of each form of ethylenediamine in this solution at equilibrium. [H2NCH,CH,NH2] = [H2NCH,CH,NH+] = [HẸNCH,CH,NH] = M M M

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter19: The Chemistry Of The Main-group Elements
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Calculate the pH of a 0.295 M solution of ethylenediamine (H₂NCH,CH,NH₂). The pKa values for the acidic form of
ethylenediamine (HNCH,CH,NH) are 6.848 (pKa1) and 9.928 (pKa2).
pH =
Calculate the concentration of each form of ethylenediamine in this solution at equilibrium.
[H2NCH2CH2NH₂] =
[H2NCH,CH,NH] =
[HNCH,CH,NH3] =
M
M
M
Transcribed Image Text:Calculate the pH of a 0.295 M solution of ethylenediamine (H₂NCH,CH,NH₂). The pKa values for the acidic form of ethylenediamine (HNCH,CH,NH) are 6.848 (pKa1) and 9.928 (pKa2). pH = Calculate the concentration of each form of ethylenediamine in this solution at equilibrium. [H2NCH2CH2NH₂] = [H2NCH,CH,NH] = [HNCH,CH,NH3] = M M M
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