calculate the pH of theConcentrahun of n = 0.lmol/LMean titre (NOH solution)=18,95 mL n!Amount of Na0H= 0.00199 molesr raho of Naok: aspirin=1:1equivalence pointドヤN2OH SolutionMolarNa0f: aspinin=ブすAmount ofaspirin=0.0a/89 molesMasMass of aspiin lin titration) = 0,341 4Mass 19of Aspinin (per toblet) =0,34

Aspirin is a weak acid. It is reacting with a strong base NaOH. So, the equivalence point will be…

calculate the pH of the equivalence pount concentraton of N2OH solution = oil mollL Mean tire (NoOH solution)= 18,95 mL ! Amount of Na0H=0.00199 moles Molar rotio of Naok: aspirin=1:7 Amount of aspirin= 0.00189 nioles Mass of aspirin Cin titrabon) = 0,34 4 Mass of Aspirin (per tablet) = 0,341g %3D %3D

calculate the pH of the equivalence pount concentraton of N2OH solution = oil mollL Mean tire (NoOH solution)= 18,95 mL ! Amount of Na0H=0.00199 moles Molar rotio of Naok: aspirin=1:7 Amount of aspirin= 0.00189 nioles Mass of aspirin Cin titrabon) = 0,34 4 Mass of Aspirin (per tablet) = 0,341g %3D %3D

Chemistry: Principles and Practice

3rd Edition

ISBN:9780534420123

Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Chapter16: Reactions Between Acids And Bases

Section: Chapter Questions

Problem 16.52QE

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