Calculate the potential for a redox titration when 100.0 mL of 0.00100 M NO₂ solution is titrated using 5.00 mL of 0.00400 M Ce**. Ce+ (aq) +eCe³+ (aq) E-1.72 V NO₂ (aq) + 2e = NO₂ (aq) E-0.940 V O 0.87 V O-0.87 V O 1.65 V O 0.96 V O-1.65 V

Chemistry: Principles and Practice
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Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
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Chapter18: Electrochemistry
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Problem 18.98QE
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Calculate the potential for a redox titration when 100.0 mL of 0.00100 M NO₂ solution is
titrated using 5.00 mL of 0.00400 M Ce**.
Ce+ (aq) +eCe³+ (aq)
E-1.72 V
NO₂ (aq) + 2e = NO₂ (aq)
E-0.940 V
O 0.87 V
O-0.87 V
O 1.65 V
O 0.96 V
O-1.65 V
Transcribed Image Text:Calculate the potential for a redox titration when 100.0 mL of 0.00100 M NO₂ solution is titrated using 5.00 mL of 0.00400 M Ce**. Ce+ (aq) +eCe³+ (aq) E-1.72 V NO₂ (aq) + 2e = NO₂ (aq) E-0.940 V O 0.87 V O-0.87 V O 1.65 V O 0.96 V O-1.65 V
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