Calculate the pressure (in atm) at which the freezing temperature of water is -20°C = 253 K.H₂O(s)→ H₂O(l) AH°f (= AHM)V solid1.963x10-5 m³/moleVliquid 1.800x10-5 m³/mole===Caution: signs and units6010 J/mole at TM = 273 K,(fusion = melting)Assume AH°f, Av₁ = V₁ - Vs are constant · ·1 atm=1.013×105 Pa= 1 atm

To find out the pressure of at which the freezing temperature of water becomes -20°C that is equal…

Calculate the pressure (in atm) at which the freezing temperature of water is -20°C = 253 K. H₂O(s)→ H₂O(1) AH°f (= AHM) = 6010 J/mole at TM = 273 K, P = 1 atm (fusion = melting) V solid 1.963x10-5 m³/mole Vliquid 1.800x10-5 m³/mole = = Assume AH°f, Avf=V₁ - Vs are constant.. 1 atm = 1.013x105 Pa Caution: signs and units

Calculate the pressure (in atm) at which the freezing temperature of water is -20°C = 253 K. H₂O(s)→ H₂O(1) AH°f (= AHM) = 6010 J/mole at TM = 273 K, P = 1 atm (fusion = melting) V solid 1.963x10-5 m³/mole Vliquid 1.800x10-5 m³/mole = = Assume AH°f, Avf=V₁ - Vs are constant.. 1 atm = 1.013x105 Pa Caution: signs and units

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter17: Spontaneity, Entropy, And Free Energy

Section: Chapter Questions

Problem 128IP: Some nonelectrolyte solute (molar mass = 142 g/mol) was dissolved in 150. mL of a solvent (density =...

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