Calculate the solubility product (Ksp) for magnesium hydraxide at 298.15 K from the electrochemical cell: Mg (s) | Mg(OH)2 (s) | NAOH (aq) || MBCI2 (aq) | Mg (s) given that E° for the reduction half-cell reaction is -2.400 V and E° for the oxidation side is -2.690 V at 298.15 K. You can assume that the solutions are ideal.

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter18: Electrochemistry
Section: Chapter Questions
Problem 18.101QE: At 298 K, the solubility product constant for PbC2O4 is 8.5 1010, and the standard reduction...
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Question 18 (
Calculate the solubility product (Ksp) for magnesium hydraxide at 298.15 K from the
electrochemical cell:
Mg (s) | Mg(OH)2 (s) | NAOH (aq) || MgCl2 faq) | Mg (s)
given that E° for the reduction half-cell reaction is -2.400 V and E° for the oxidation
side is -2.690 V at 298.15 K. You can assume that the solutions are ideal.
Enter in your answer to 2 decimal places in units of x1011.
Your Answer:
Answer
Question 19 ("
Calculate AU for 7.56 mol of a gas at 298.15 K that is heated under standard
conditions until it reaches a final temperature of 394.2 K. The heat capacity for this
gas is:
Cm(T)
JK-1 mol-i T
= 22. 68 + 0. 3541
Enter your answer to one decimal place in units of kJ.
(Hint: You will need to use AU = q +w to solve this question.)
Your Answer:
Answer
Transcribed Image Text:Question 18 ( Calculate the solubility product (Ksp) for magnesium hydraxide at 298.15 K from the electrochemical cell: Mg (s) | Mg(OH)2 (s) | NAOH (aq) || MgCl2 faq) | Mg (s) given that E° for the reduction half-cell reaction is -2.400 V and E° for the oxidation side is -2.690 V at 298.15 K. You can assume that the solutions are ideal. Enter in your answer to 2 decimal places in units of x1011. Your Answer: Answer Question 19 (" Calculate AU for 7.56 mol of a gas at 298.15 K that is heated under standard conditions until it reaches a final temperature of 394.2 K. The heat capacity for this gas is: Cm(T) JK-1 mol-i T = 22. 68 + 0. 3541 Enter your answer to one decimal place in units of kJ. (Hint: You will need to use AU = q +w to solve this question.) Your Answer: Answer
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