Calculate the standard enthalpy change for the reaction 2C8H18() + 1702(g) -16CO(g) + 18H20(). Given 2C;H1s(1)+2502g)→16CO:(g) + 18H;O() AH° =-11,020 kJ/mol 2C0g) + 0:(g) → 2CO:(g) AH° =-566.0 kJ/mol

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter4: Energy And Chemical Reactions
Section4.10: Standard Formation Enthalpies
Problem 4.18CE
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Calculate the standard enthalpy change for the reaction
2C3H18() + 1702(g) –-16CO(g) + 18H20).
Given
2C3H1S(1)+ 2502(g)→16CO2(g) + 18H;O) AH° = -11,020 kJ/mol
2C0(g) + 02(g) → 2co:(g)
AH° = -566.0 kJ/mol
Multiple Choice
6,492 kJ/mol
15,550 kJ/mol
-6,492 kJ/mol
-10.450 kJ/mol
10,450 kJ/mol
Transcribed Image Text:Calculate the standard enthalpy change for the reaction 2C3H18() + 1702(g) –-16CO(g) + 18H20). Given 2C3H1S(1)+ 2502(g)→16CO2(g) + 18H;O) AH° = -11,020 kJ/mol 2C0(g) + 02(g) → 2co:(g) AH° = -566.0 kJ/mol Multiple Choice 6,492 kJ/mol 15,550 kJ/mol -6,492 kJ/mol -10.450 kJ/mol 10,450 kJ/mol
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