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Calculate the standard enthalpy of formation of liquid methanol, CH3OH(I), using the following information: 5. C (graphite) + 2H2(g) + 1/2 O2(g) → CH3OH(I) Given: C (graphite) + O2 - CO2(g) H2(g) + 2 O2 H20(1) CH:OH(I) + 3/2 02(g) - CO2(g) + 2H20(1) AH° = -393.5 kJ/mol AH° = -285.8 kJ/mol AH° = -726.4 kJ/mol

Calculate the standard enthalpy of formation of liquid methanol, CH3OH(I), using the following information: 5. C (graphite) + 2H2(g) + 1/2 O2(g) → CH3OH(I) Given: C (graphite) + O2 - CO2(g) H2(g) + 2 O2 H20(1) CH:OH(I) + 3/2 02(g) - CO2(g) + 2H20(1) AH° = -393.5 kJ/mol AH° = -285.8 kJ/mol AH° = -726.4 kJ/mol

Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter5: Principles Of Chemical Reactivity: Energy And Chemical Reactions
Section5.7: Enthalpy Calculations
Problem 5.10CYU: Calculate the standard enthalpy of combustion for benzene, C6H6. C6H6() + 15/2 O2(g) 6 CO2(g) + 3...
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Calculate the standard enthalpy of formation of liquid methanol, CH3OH(I), using the following information: 5. C (graphite) + 2H2(g) + 1/2 O2(g) CH3OH(I) Given: C (graphite) + 02 - CO2(g) H2(g) + 2 O2 H20(1) CH3OH(I) + 3/2 02(g) CO2(g) + 2H20(1) AH° = -393.5 kJ/mol AH° = -285.8 kJ/mol AH° = -726.4 kJ/mol 6. Calculate AH for this reaction: CH4(g) + NH3(g)→ HCN(g) + 3H2(g) Given: N2(g) + 3 H2(g) →2 NH3(g) C(s) + 2 H2(g) → CH4(g) H2(g) + 2 C(s) + N2(g) AH = -91.8 kJ AH = -74.9 kJ → 2 HCN(g) AH = +270.3 kJ
Transcribed Image Text:Calculate the standard enthalpy of formation of liquid methanol, CH3OH(I), using the following information: 5. C (graphite) + 2H2(g) + 1/2 O2(g) CH3OH(I) Given: C (graphite) + 02 - CO2(g) H2(g) + 2 O2 H20(1) CH3OH(I) + 3/2 02(g) CO2(g) + 2H20(1) AH° = -393.5 kJ/mol AH° = -285.8 kJ/mol AH° = -726.4 kJ/mol 6. Calculate AH for this reaction: CH4(g) + NH3(g)→ HCN(g) + 3H2(g) Given: N2(g) + 3 H2(g) →2 NH3(g) C(s) + 2 H2(g) → CH4(g) H2(g) + 2 C(s) + N2(g) AH = -91.8 kJ AH = -74.9 kJ → 2 HCN(g) AH = +270.3 kJ
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