Calculate the standard enthalpy of formation of solid diboron trioxide (B2O3) using the following thermochemical information: B2H6(g) + 3 O2(g) (equilibrium arrows) B2O3(s) + 3 H2O(l)        H = -2147.5 kJ 2 H2O(l)(equilibrium arrows)  2 H2(g) + O2(g)                                  H = +571.7 kJ B2H6(g)(equilibrium arrows)  2 B(s) + 3 H2(g)                                 H = -35.4 kJ

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