The form of the partial fraction decomposition of a rational function is given below. A = B Now evaluate the indefinite integral. 2x √ (32²=² + 2(22=+=+²20) 4) -dx = 3x²+2x+ 20 (x − 1)(x² + 4) 1. ← = A x - 1 C = + Bx + C x² + 4 ←

College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter5: Systems Of Equations And Inequalities
Section5.3: Partial Fractions
Problem 7E
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The form of the partial fraction decomposition of a rational function is given below.
A
=
B
Now evaluate the indefinite integral.
2x
√ (32²=² + 2(22=+=+²20)
4)
-dx =
3x²+2x+ 20
(x − 1)(x² + 4)
1.
←
=
A
x - 1
C =
+
Bx + C
x² + 4
←
Transcribed Image Text:The form of the partial fraction decomposition of a rational function is given below. A = B Now evaluate the indefinite integral. 2x √ (32²=² + 2(22=+=+²20) 4) -dx = 3x²+2x+ 20 (x − 1)(x² + 4) 1. ← = A x - 1 C = + Bx + C x² + 4 ←
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