Answered: Can some one please help filling in the…

Inquiry into Physics

8th Edition

ISBN:9781337515863

Author:Ostdiek

Publisher:Ostdiek

Chapter12: Relativity, Particle Physics, And Cosmology

Section: Chapter Questions

Problem 6P

See similar textbooks

Related questions

Concept explainers

Question

100%

Can some one please help filling in the empty graph. The other one is to help fill in the empty one . The 6 things I'm listing aren't questions just directions to understand . 1. Correctly round all of your TE values in Trial 5 to a whole number. Correctly round all of your TE values in Trial # 7 to a one decimal place only. 2. Compare the 5 TE values for each trial. Choose the trial in which your 5 TE values are the most similar. This will be your CHOSEN trial . 3. Once you have decided on the trial with the closest 5 TE values, create a bar graph on the attached graph paper. I have labeled the X- axis for you. Notice that you will have a PE, KE, and TE bar for each point. 4. You will have to decide on the numbers for the Yaxis. Type numbers in the blank column on the left of the graph . 5. Remember to title your graph "Y - axis variable name vs X-axis variable name." That is not the actual title, just the template for you to use to write your title. 6. Please make your PE bars pink your KE bars green and your TE bars yellow

Point on
trajectory
Point 1
Point 2
Point 3
Point 4
Point 5
Point on
trajectory
Point 1
Point 2
Point 3
Position (m)
[height]
0.683
Point 4
Point 5
0.818
0.856
0.799
0.651
Data Table 3: Trajectory Points for Trial 7
0.589
Velocity
(m/s)
1.806
0.869
0.628
-0.092
0.575
0.428
-1.026
Position (m) Velocity
[height]
(m/s)
0.0454
1.733
-1.895
0.869
-0.063
-1.002
-1.709
Trial 5
PE (J)
PE=mgh
1.00401 J
1.20246 J
1.858 J
1.17459 J
0.956
Trial 7
PE (J)
PE=mgh
0.0668 J
0.8658 J
0.924 J
0.846 J
0.629 J
KE (J)
KE=1/2mv²
0.244 J
0.0566 J
0.0006348 J
0.0789 J
0.2699 J
KE (J)
KE=1/2mv²
0.225 J
0.0566 J
0.000297 J
0.075 J
0.219 J
TE (J)
TE=PE+KE
1.24801 J
1.259 J
1.2586 J
1.25348 J
1.2262 J
TE (J)
TE=PE+KE
0.3 J
0.9 J
0.9 J
0.9 J
0.8 J

PE
ΚΕ
Point 1
TE
PE KE
Point 2
TE
KE TE
Point 3
Types of Energy
PE
PE KE TE
Point4
PE
KE TE
Point 5

Expert Solution

Step by step

Solved in 3 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions