Force m (g) w (N) = mg θ (°) F1 60.0g = 0.06kg 0.588N 95° F2 75.0g = 0.075kg 0.735N 215° F3 70.0g = 0.070kg 0.686N 340° Solve for the resultant of F1 and F2 using the analytical method (triangle trigonometry using sine and cosine laws or component method). Assign this as RB.

Force m (g) w (N) = mg θ (°) F1 60.0g = 0.06kg 0.588N 95° F2 75.0g = 0.075kg 0.735N 215° F3 70.0g = 0.070kg 0.686N 340° Solve for the resultant of F1 and F2 using the analytical method (triangle trigonometry using sine and cosine laws or component method). Assign this as RB.

University Physics Volume 3

17th Edition

ISBN:9781938168185

Author:William Moebs, Jeff Sanny

Publisher:William Moebs, Jeff Sanny

Chapter1: The Nature Of Light

Section: Chapter Questions

Problem 34P: Suppose a man stands in front of a mm-or as show below. His eyes are 1.65 m above the floor and the...

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Question

Force	m (g)	w (N) = mg	θ (°)
F1	60.0g = 0.06kg	0.588N	95°
F2	75.0g = 0.075kg	0.735N	215°
F3	70.0g = 0.070kg	0.686N	340°

Solve for the resultant of F1 and F2 using the analytical method (triangle trigonometry using sine and cosine laws or component method). Assign this as RB.

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