Problem 6.3 Use the concept of the phasor to combine the following sinusoidal functions into a single trigonometric expression: a.) y = 30 cos(200t – 160°) + 15 cos(200t + 70°). b.) y = 90 sin(50t – 20°) + 60 cos(50t – 70°). c.) y = 50 cos(5000t - 60°) + 25 sin(5000t + 110°) - 75 cos(5000t - 30°). d.) y = 10 cos(wt + 30°) + 10 sin wt + 10 cos(wt + 150°). %3D

Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter2: Fundamentals
Section: Chapter Questions
Problem 2.3MCQ: If a phasor representation of a current is given by I=70.745A, it is equivalent to a. 100e/45 b....
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Problem 6.3 Use the concept of the phasor to combine the following sinusoidal
functions into a single trigonometric expression:
a.) y = 30 cos(200t 160°) + 15 cos(200t + 70°).
b.) y = 90 sin(50t – 20°) + 60 cos(50t – 70°).
c.) y = 50 cos(5000t – 60°) + 25 sin(5000t + 110°) – 75 cos(5000t – 30°).
d.) y = 10 cos(@t + 30°) + 10 sin wt + 10 cos(wt + 150°).
%3D
%3D
Transcribed Image Text:Problem 6.3 Use the concept of the phasor to combine the following sinusoidal functions into a single trigonometric expression: a.) y = 30 cos(200t 160°) + 15 cos(200t + 70°). b.) y = 90 sin(50t – 20°) + 60 cos(50t – 70°). c.) y = 50 cos(5000t – 60°) + 25 sin(5000t + 110°) – 75 cos(5000t – 30°). d.) y = 10 cos(@t + 30°) + 10 sin wt + 10 cos(wt + 150°). %3D %3D
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can you please go into more detail for each problem..

im not understanding how to calculate after the expression is put into the frequency domain, explain the math also how to insert it in a calculator 

how did we go from30 angle -160 degree into 23.38 angle 170.55 degrees 

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