Can you resolve?5-bit ADC, Vn=0.6V, Vret=1Example (2)Cycle 1 => MSB=1SAR = 10000VDAC = Vres/21 = .5Vin > VDAC SAR unchanged = 1000• Cycle 2SAR = 1100 0VOAC = .5 +.25 = .75Vn < VDAC SAR bit3 reset to 0 = 1000• Cycle 3SAR = 10100VOAC = .5 + .125 = .625Vn < VDACSAR bit2 reset10000• Cycle 4SAR = 10010VOAC = .5+.0625=.5625Vn > VDACnchanged = 1 0010• Cycle 5SAR = 100 11VDAC = .5+.0625+.03125= ,59375DENTS D INSERUMATBit4Voltage.5.0625.03125

For 5 bit ADC the required cycles will be 5. I have underlined the bit which is going to be either…

Can you resolve? 5-bit ADC, V=0.6V, Ve=1 Cycle 1 => MSB=1 SAR = 10000 VDAC = Vres21 = .5 Vin > VDAC SAR unchanged =10000 Cycle 2 SAR = 1100 0 VOAC = .5 +.25 = .75 Vn < VDAC SAR bit3 reset to 0 = 1000 Cycle 3 SAR = 1010 0 VDAC = .5 + .125 = .625 Vn < VDAc SAR bit2 reset to 0 = 10000 • Cycle 4 SAR = 10010 VOẠC = .5+.0625=.5625 Vn > VDAC SAR unchanged 100 10 • Cycle 5 SAR = 100 11 ENTSND INSERUM VOAC = .5+.0625+.03125= 59375 Bit 4 Voltage .5 .125 .0625 .03125

Can you resolve? 5-bit ADC, V=0.6V, Ve=1 Cycle 1 => MSB=1 SAR = 10000 VDAC = Vres21 = .5 Vin > VDAC SAR unchanged =10000 Cycle 2 SAR = 1100 0 VOAC = .5 +.25 = .75 Vn < VDAC SAR bit3 reset to 0 = 1000 Cycle 3 SAR = 1010 0 VDAC = .5 + .125 = .625 Vn < VDAc SAR bit2 reset to 0 = 10000 • Cycle 4 SAR = 10010 VOẠC = .5+.0625=.5625 Vn > VDAC SAR unchanged 100 10 • Cycle 5 SAR = 100 11 ENTSND INSERUM VOAC = .5+.0625+.03125= 59375 Bit 4 Voltage .5 .125 .0625 .03125

Electricity for Refrigeration, Heating, and Air Conditioning (MindTap Course List)

10th Edition

ISBN:9781337399128

Author:Russell E. Smith

Publisher:Russell E. Smith

Chapter17: Commercial And Industrial Air-conditioning Control Systems

Section: Chapter Questions

Problem 25RQ

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