Question
Asked Nov 7, 2019
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Ch 21, Problem 03

Review Conceptual Example 2 as an aid in understanding this problem. The drawing shows a positively charged particle entering a 0.71-T magnetic field. The particle has a speed of 240 m/s and moves perpendicular to the magnetic field. Just as the particle enters the magnetic field, an electric field is turned on. What must be the magnitude of the electric field such that the net force on the particle is twice the magnetic force?

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Expert Answer

Step 1

Let v be the speed of the charged particle, q be the charge on the particle, E be the magnitude of electric field, B be the magnetic field, F be the net force.

Write the given values of question.

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v 240 m/s B 0.71 T

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Step 2

Write the expression for the magnetic force and the net force on the charged particle.

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F F qEqvB

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Step 3

Write the expression for the given conditi...

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F 2F q(EB) 2vB E =B (240 m/s)(0.71 T) =170.4 N/C

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